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Question

The de-broglie wavelength of an electron and the wavelength of a photon are same. The ratio between the energy of the photon and the momentum of the electron is

A
h
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B
c
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C
1/h
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D
1/c
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Solution

The correct option is B c
De-broglie wavelength :
λ=hp

λe=hmeV

and for proton

λp=hcE

given λe=λp

hmeV=hcE

EPe=c
So, the answer is option (B).

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