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Question

The de-Broglie wavelength of an electron and the wavelength of a photon are the same. The ratio between the energy of that photon and the momentum of that electron is (c =velocity of light, h= Planck's constant)

A
h
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B
c
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C
1c
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D
None of these
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Solution

The correct option is B c
We have λe=hmv
and λp=hmc
According to the question,
λe=λp
v=c
EpPe=mc2mv=c2c=c

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