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The de-Broglie wavelength of an electron having 80eV of energy is nearly (leV=1.6×1019J Mass of electron 9×1031kg and Plank's constant 6.6×1034Jsec)
  1. 0.14A
  2. 14A
  3. 140A
  4. 1.4A


Solution

The correct option is D 1.4A
By using λ=h2mE=12.27V. If energy is 80 eV then accelerating potential difference will be 80 V. So
λ=12.2780=1.371.4A.

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