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Byju's Answer
Standard XII
Physics
Rutherford's Model
The de-Brogli...
Question
The de-Broglie wavelength of an electron in the ground state of the hydrogen atom is :
A
π
r
2
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B
2
π
r
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C
π
r
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D
√
π
r
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Solution
The correct option is
B
2
π
r
Bohr's postulate for angular momentum states,
m
v
r
=
n
h
2
π
For ground state, momentum of electron
=
p
=
m
v
=
h
2
π
r
Thus de-broglie wavelength for the electron is
h
p
=
2
π
r
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1
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