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Question

The de broglie wavelength of an electron (initially at rest) accelerated by an electric potential of 9 volts is given by:
Given: me=9.1×1031 kg, e=1.6×1019 C,
h=6.6×1031 Js

A
0.87 nm
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B
0.62 nm
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C
0.41 nm
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D
0.14 nm
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