The de Broglie wavelength of an electron moving with a velocity 0f 1.5X108 m/s is equal to that of a photon. The ratio of kinetic energy of that electron to the photon is.
[IIT JEE 2004]
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Given λe=λp
⇒hmev=hcE …(1)
(∵ P = hλ, for electron
E = hcλ, for photon)
From eqn(1)E=mevc ……(II)
Now ratio of electron energy to photon = 12meV2E
from eqn(II)
⇒12meV2meVC
⇒12VC=121.5x1083x108
⇒14