wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The de Broglie wavelength of an electron moving with a velocity 0f 1.5X108 m/s is equal to that of a photon. The ratio of kinetic energy of that electron to the photon is.

[IIT JEE 2004]


A

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1/2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

1/4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

1/4


Given λe=λp
hmev=hcE …(1)
(∵ P = hλ, for electron
E = hcλ, for photon)

From eqn(1)E=mevc ……(II)

Now ratio of electron energy to photon = 12meV2E
from eqn(II)
12meV2meVC
12VC=121.5x1083x108
14


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Matter Waves
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon