wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The deactivation of ascorbic acid follows first order kinetics. 25 mL sample of juice is kept for 2 months and after 2 months, on titration with same KIO3 in presence of 1MHCl solution requires 0.5 mL of KIO3 solution. The average life of fruit juice is :

A
60 days
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
54.6 days
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
86.5 days
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
120 days
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 54.6 days
166 mL sample of fresh juice requires 10 mL of KIO3.
25 mL of sample of fresh juice will require =25166×10=1.5 mL of KIO3.
After 2 months, 25 mL of sample of fresh juice requires 0.5 mL of KIO3.
Hence, k=2.303tlogaax for first order kinetics.
k=2.30360log1.50.5=0.0183
The average life is 1k=10.0183=54.6 days.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integrated Rate Equations
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon