The deamination of $P h_{2} C (O H) C H_{2} N H_{2}$ with $N a N O_{2} - H C l$ gives a product $(P)$ , which on oxidation gives benzoic acid only. Identify the product $(P)$ .

P h - C H_{2} - C H_{2} - P h

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P h - O | | C - C H_{2} - P h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P h - O | | C - O | | C - P h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P h - C H_{2} - N H - P h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $P h - C H_{2} - C H_{2} - P h$
In this reaction $N a N O_{2}$ along with $H C l$ is used which is mainly used for diazotization reaction. It converts aromatic amine into a diazonium ion. This is followed by its oxidation which leads to the formation of benzoic acid. $(P h - C O O H)$

Suggest Corrections

Similar questions

P h - O - C H_{2} - P h

H I

Aniline N a N O_{2} - --- \to H C l A C u C N - --- \to B H_{2} - \to N i C H N O_{2} - --- \to D

P H - O | | C - C H_{2} - O | | C - O H

P h - N H - O H

P h - C H O

H - O | | C - O H

O H | C H_{2} - O | | C - C H_{3}

Aniline C H C l_{3}, K O H - ------- \to Δ X L i A l H_{4} - --- \to Y

(Y)

Join BYJU'S Learning Program