Question

The deBroglie wavelength associated with a particle of mass m, moving with a velocity ${}^{\prime }v{}^{\prime }$ and energy E is given by

• A. $\frac{h}{m{v}^2}$
• B. $\frac{mv}{h^2}$
• C. $\frac{h}{\sqrt{2mE}}$
• D. $\sqrt{2mE}/h$

Answer 1

The correct option is C $\frac{h}{\sqrt{2mE}}$

We know,
$\frac{1}{2}m{v}^2=E$
$mv=\sqrt{2Em}$
so debroglie wavelength $\left(\lambda \right)=\frac{h}{mv}$
$=\frac{h}{\sqrt{2Em}}$