Question

The decay modes of ${}^{14}C$ and ${}^{14}O$ are

• A. $\beta$ decay
• B. positron emission
• C. $\beta$ decay and positron emission, respectively
• D. positron emission and $\beta$ decay, respectively

Answer 1

The correct option is A $\beta$ decay

For c- 14 isotope there is exess neutron.. So the neutron will be ejected giving out Proton and an electron...
That is it is beta - emission.
For O-14 isotope it is deficient in neutrons and rich in protons.. So Proton will be transformed to neutron and positron.
That is positron emission or beta + emission.