The decay profiles of three radioactive species A, B and C are given : These profiles imply that the decay constants kA,kB and kC follow the order
A
kA>kB>kC
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B
kA>kC>kB
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C
kB>kA>kC
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D
kC>kB>kA
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Solution
The correct option is DkC>kB>kA The option (D) is the correct answer.
These profiles imply that the decay constants follow the order kC>kB>kA The curve for C has a lower slope than the curve for A.
For a given amount of time, the concentration of A is more than the concentration of C. Hence the rate of decay of A is less than the rate of decay of B.