Question

The decimal expansion of $\frac{141}{120}$ will terminate after how many places?

• A. 3
• B. 5
• C. 7
• D. Will not terminate

Answer 1

The correct option is A

3

Given rational number $\frac{141}{120}$

Here, $120=2^3\times 3\times 5$

$141=3\times 47$

$\Rightarrow$ $\frac{141}{120}$ = $\frac{3\times 47}{2^3\times 3\times 5}$

= $\frac{47}{2^3\times 5}$

Multiply and divide by $5^2$.

=$\frac{47\times 5^2}{2^3\times 5\times 5^2}$

= $\frac{47\times 25}{(2\times 5{)}^3}$

= $\frac{1175}{1000}$

= 1.175

Therefore, $\frac{141}{120}$ will terminate after three decimal places.