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Question

The decomposition of 2N2O52N2O4+O2 is at 200oC. If the initial pressure is 114 mm and after 25 min. of the reaction the total pressure of gaseous mixture is 133 mm. Calculate the average rate of the reaction in

a) atm min1 b) mol L1s1 respectively.

A
0.002,8.58×107
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B
0.001,8.58×107
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C
0.002,8.58×104
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D
0.001,8.58×103
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Solution

The correct option is A 0.002,8.58×107
The decomposition reaction is 2N2O52N2O4+O2.
The inital number of moles of N2O5,N2O4 and O2 are ax, x and x2 respectively.
After 25 min, the number of moles are a+x2. The pressure is 133 mm.
Thus the pressure due to x2 moles corresponds to 133114=19 mm Hg.
The pressure due to x moles corresponds to 19×2=38 mm Hg.
Pressure due to (a-x) moles =11476=38 mm Hg.
The average rate of the reaction is =3825×760=0.002 atm min1.
The ideal gas equation is PV=nRT.
nV=0.0020.0821×473×60=8.58×107mol lit1s1.

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