The decomposition of 2N2O5→2N2O4+O2 is at 200oC. If the initial pressure is 114 mm and after 25 min. of the reaction the total pressure of gaseous mixture is 133 mm. Calculate the average rate of the reaction in
a) atmmin−1 b) molL−1s−1 respectively.
A
0.002,8.58×10−7
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B
0.001,8.58×10−7
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C
0.002,8.58×10−4
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D
0.001,8.58×10−3
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Solution
The correct option is A0.002,8.58×10−7 The decomposition reaction is 2N2O5→2N2O4+O2.
The inital number of moles of N2O5,N2O4 and O2 are a−x,x and x2 respectively.
After 25 min, the number of moles are a+x2. The pressure is 133 mm.
Thus the pressure due to x2 moles corresponds to 133−114=19 mm Hg.
The pressure due to x moles corresponds to 19×2=38 mm Hg.
Pressure due to (a-x) moles =114−76=38 mm Hg.
The average rate of the reaction is =3825×760=0.002atmmin−1.