The decomposition of dimethyl ether leads to the formation of $C H_{4}, H_{2}$ and CO and the reaction rate is given
By rate = $K [C H_{3} O C H_{3}]^{\frac{3}{2}}$
The rate of reaction is followed by increase in pressure in a closed vessel and the rate can be expressed in terms of the partial pressure of dimethyl ether i.e, Rate = $K (p_{C} H_{3} O C H_{3})^{\frac{3}{2}}$
If pressure is measured in bar and time in minutes, the units of rate constant are

(b a r)^{\frac{3}{2}} m i n^{- 1}

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(b a r)^{-} \frac{3}{2} m i n^{- 1}

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(b a r)^{-} \frac{1}{2} m i n^{- 1}

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(b a r)^{- 1} m i n^{- 1}

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Solution

The correct option is C $(b a r)^{-} \frac{1}{2} m i n^{- 1}$
Rate= $k (p C H_{3} O C H_{3})^{\frac{3}{2}}$
$\frac{b a r}{m i n} = k (b a r)^{\frac{3}{2}} \Rightarrow k = (b a r)^{\frac{- 1}{2}} m i n^{- 1}$

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Rate = k [CH₃OCH₃]^3/2

The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e.,

If the pressure is measured in bar andtime in minutes, then what are the units of rate and rate constants?

Q. The decomposition of dimethyl ether leads to the formation of

C H_{4}, H_{2}

and CO and the reaction rate is given
By rate =

K [C H_{3} O C H_{3}]^{\frac{3}{2}}

The rate of reaction is followed by increase in pressure in a closed vessel and the rate can be expressed in terms of the partial pressure of dimethyl ether i.e, Rate =

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If pressure is measured in bar and time in minutes, the units of rate constant are

The decomposition of dimethyl ether leads to the formation of $C H_{4}$ , $H_{2}$ and $C O$ and the reaction rate is given by:

Rate $= k [C H_{3} O C H_{3}]^{\frac{3}{2}}$ . The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can be expressed in terms of the partial pressure of dimethyl ether i.e. Rate = $k (p_{C H_{3} O C H_{3}})^{\frac{3}{2}}$ . If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?

Q. The decomposition of dimethyl ether leads to the formation of

C H_{4}, H_{2}

and

C O

and the reaction rate is given by:

R a t e = k [C H_{3} O C H_{3}]^{3 / 2}

The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether.

i.e.,

R a t e = k [P_{C H_{3} O C H_{3}}]^{3 / 2}

If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?

Q. The decomposition of dimethyl ether is a fractional-order reaction. The rate of reaction is given by

R a t e = k (p_{C H_{3} O C H_{3}})^{3 / 2}

. If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant?

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The correct option is C (bar)−12min−1Rate=k(pCH3OCH3)32 barmin=k(bar)32⇒k=(bar)−12min−1

The correct option is C $(b a r)^{-} \frac{1}{2} m i n^{- 1}$
Rate= $k (p C H_{3} O C H_{3})^{\frac{3}{2}}$
$\frac{b a r}{m i n} = k (b a r)^{\frac{3}{2}} \Rightarrow k = (b a r)^{\frac{- 1}{2}} m i n^{- 1}$