The decomposition of hydrocarbon follows the equation k -4-5 - 1011 s -1 e -28000 K - T- Calculate the activation energy E a

According to Arrhenius equation k = Ae^ E_a/RT…… (i) According to the available data k = (4.5 × 10^11s^ 1)e^ 28000K/T …… (ii) On comparing both equations; E_a/ ...

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Standard XII

Chemistry

Arrhenius Equation

The decomposi...

Question

The decomposition of hydrocarbon follows the equation $k = (4.5 \times 10^{11} s^{- 1}) e^{- 28000} K / T$ . Calculate the activation energy $E_{a}$

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Solution

According to Arrhenius equation
$k = A e^{\frac{- E_{a}}{R T}} \dots \dots (i)$
According to the available data
$k = (4.5 \times 10^{11} s^{- 1}) e^{- 28000} K / T \dots \dots (i i)$
On comparing both equations;
$- \frac{E_{a}}{R T} = \frac{- 28000 K}{T} E_{a} = (28000 K) \times R = (28000 K) \times (8.314 K^{- 1} J m o l^{- 1}) = 232792 J k m o l^{- 1} E_{a} = 232.792 k J^{- 1} m o l^{- 1}$

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The decomposition of hydrocarbon follows the equation k=(4.5×1011s−1)e−28000 K/T. Calculate the activation energy Ea

According to Arrhenius equation k=Ae−EaRT……(i) According to the available data k=(4.5×1011s−1)e−28000K/T……(ii) On comparing both equations; −EaRT=−28000KTEa=(28000K)×R=(28000K)×(8.314 K−1Jmol−1)=232792 Jk mol−1Ea=232.792 kJ−1 mol−1

The decomposition of hydrocarbon follows the equation $k = (4.5 \times 10^{11} s^{- 1}) e^{- 28000} K / T$ . Calculate the activation energy $E_{a}$