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Byju's Answer
Standard XII
Chemistry
Order of Reaction
The decomposi...
Question
The decomposition of
N
H
3
on finely divided platinum follows the rate expression,
Rate
=
k
1
[
N
H
3
]
1
+
k
2
[
N
H
3
]
It is a first order reaction when concentration of
N
H
3
is:
A
very low
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B
very high
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C
moderate
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D
never
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Solution
The correct option is
B
very low
At very low concentration of
N
H
3
,
k
2
[
N
H
3
]
<
<
1
and
1
+
k
2
[
N
H
3
]
≈
1
So,
R
a
t
e
=
k
1
[
N
H
3
]
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Similar questions
Q.
Match the column
The decomposition of ammonia on platinum surface follow the change,
2
N
H
3
⟶
N
2
+
3
H
2
; K = 2.5
10
−
4
M
S
−
1
&
−
d
[
N
H
3
]
d
t
=
K
1
[
N
H
3
]
1
+
K
2
[
N
H
3
]
,
where
K
1
and
k
2
are constant.
Q.
The decomposition of NH3 on platinum surface is zero order reaction. If rate constant (k) is
4
×
10
−
3
m
s
−
1
, how long will it take to reduce the initial concentration of
N
H
3
from 0.1 M to 0.064 M.
Q.
For a reaction,
2
N
H
3
⟶
N
2
+
3
H
2
, it is observed that:
−
d
[
N
H
3
]
d
t
=
k
1
[
N
H
3
]
,
d
[
N
2
]
d
t
=
k
2
[
N
H
3
]
,
d
[
H
2
]
d
t
=
k
3
[
N
H
3
]
.
What is the relation between
k
1
,
k
2
and
k
3
?
Q.
For the reaction,
2
N
H
3
→
N
2
+
3
H
2
−
Δ
[
N
H
3
]
Δ
t
=
K
1
[
N
H
3
]
;
Δ
[
N
2
]
Δ
t
=
K
2
[
N
H
3
]
;
Δ
[
H
2
]
Δ
t
=
K
3
[
N
H
3
]
Then relation between
k
1
,
k
2
and
k
3
is:
Q.
Decomposition of
N
H
3
on the surface of platinum has a rate constant of
2.5
×
10
−
4
m
o
l
.
d
m
−
3
s
−
1
at
350
K. The order of the reaction is:
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