The decomposition of ozone- 2O3g- 3O2g- follows the rate law- -d-O3-dt-K-O3-2-O2- Unit of K is-

The correct option is D sec^ 1 The rate law expression is as follows: #160; d[O_3]/dt=K[O_3]^2/[O_2] Substituting the units in the above expression, ...

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Standard XII

Chemistry

Order of Reaction

The decomposi...

Question

The decomposition of ozone, $2 O_{3} (g) \to 3 O_{2} (g)$ , follows the rate law: $- \frac{d [O_{3}]}{d t} = K \frac{[O_{3}]^{2}}{[O_{2}]}$ . Unit of K is:

s e c^{- 1}

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m o l^{- 1} s e c^{- 1}

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m o l s e c^{- 1}

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None of these

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Solution

The correct option is D $s e c^{- 1}$
The rate law expression is as follows:
$- \frac{d [O_{3}]}{d t} = K \frac{[O_{3}]^{2}}{[O_{2}]}$
Substituting the units in the above expression, we get
$M / s e c = K \times \frac{M^{2}}{M}$
$M / s e c = K \times M$
The unit of the rate constant $K = s e c^{- 1}$ .

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Similar questions

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, obeys the rate law

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The decomposition of ozone, 2O3(g)→3O2(g), follows the rate law: −d[O3]dt=K[O3]2[O2]. Unit of K is:

The correct option is D sec−1The rate law expression is as follows:−d[O3]dt=K[O3]2[O2]Substituting the units in the above expression, we getM/sec=K×M2MM/sec=K×MThe unit of the rate constant K=sec−1.

The decomposition of ozone, $2 O_{3} (g) \to 3 O_{2} (g)$ , follows the rate law: $- \frac{d [O_{3}]}{d t} = K \frac{[O_{3}]^{2}}{[O_{2}]}$ . Unit of K is: