The decrease in the value of g wrt earth-s surface on going to a height R2 above the earth-s surface will be-

Acceleration due to gravity at a height from the earth's surface is given by, g' = g(1 + hR)^2 At nbsp; height, h = R2 g' = g(1 + 12) = 4g9 So, decrease i ...

You visited us 7 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Application of Projectile to a Height

The decrease ...

Question

The decrease in the value of $g$ (wrt earth's surface) on going to a height $\frac{R}{2}$ above the earth’s surface will be?

\frac{g}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5 g}{9}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{4 g}{9}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{g}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{5 g}{9}$
Acceleration due to gravity at a height from the earth's surface is given by,

$g^{'} = \frac{g}{{(1 + \frac{h}{R})}^{2}}$

At height, $h = \frac{R}{2}$

$g^{'} = \frac{g}{(1 + \frac{1}{2})} = \frac{4 g}{9}$

So, decrease in the value of acceleration due to gravity $= g - g^{'}$

i.e. $= g - \frac{4 g}{9} = \frac{5 g}{9}$

Suggest Corrections

Similar questions

Q. The decrease in the value of g on going to a height

\frac{R}{2}

above the earth's surface will be:

At what height above the earth's surface the value of g will be half of that on the earth's surface ?

Q. (a) Find the height from the earth's surface where

g

will be

25 %

of its value on the surface of earth.

(

R = 6400 K m

).
(b) Find the percentage decrease in the value of

g

at a depth

h

from the surface of earth.

Periodic time of a satellite revolving above Earth’s surface at a height equal to R, where R the radius of Earth, is [g is acceleration due to gravity at Earth’s surface]

Q. Find what will be the change in the value of

g

while going

h

height over the earth's surface where

h

is in the order of

R e

Join BYJU'S Learning Program

The decrease in the value of g (wrt earth's surface) on going to a height R2 above the earth’s surface will be?

The correct option is B 5g9Acceleration due to gravity at a height from the earth's surface is given by, g′=g(1+hR)2 At height, h=R2 g′=g(1+12)=4g9 So, decrease in the value of acceleration due to gravity =g−g′ i.e. =g−4g9=5g9

The decrease in the value of $g$ (wrt earth's surface) on going to a height $\frac{R}{2}$ above the earth’s surface will be?