The decreasing basic order of the following compounds is:

$i . H_{2} O$
$i i . H_{2} S$
$i i i . H_{2} S e$
$i v . H_{2} T e$

(i) > (i i) > (i i i) > (i v)

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(i v) > (i i i) > (i i) > (i)

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(i i i) > (i) > (i i) > (i v)

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(i v) > (i i) > (i) > (i i i)

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Solution

The correct option is B $(i) > (i i) > (i i i) > (i v)$
The basic character of hydrides of 16 group decreases down the group. Size increases down the group and LP $¯ ¯ ¯ e$ density decreases.

Basic: $H_{2} O > H_{2} S > H_{2} S e > H_{2} T e$

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I.

P h O^{⊖}

II.

C H_{3} S^{⊖}

III.

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IV.

M e O^{⊖}

Q. Arrange the following oxides in the decreasing orders of their basic strength.

I . T l_{2} O

I I . A l_{2} O_{3}

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Q. Arrange the following compounds in decreasing order of their reactivity with sodium methoxide in methanol at

50^{\circ}

Mark the correct order of decreasing acid strength of the following compounds.

(a) V > IV > II > I > III
(b) II > IV > I > III > V
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Order of decreasing acidity of the following is

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(IV) ${C F}_{3} C O O H$

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The decreasing basic order of the following compounds is:i.H2O ii.H2S iii.H2Se iv.H2Te

The correct option is B (i)>(ii)>(iii)>(iv)The basic character of hydrides of 16 group decreases down the group. Size increases down the group and LP ¯¯¯e density decreases.Basic: H2O>H2S>H2Se>H2Te

The decreasing basic order of the following compounds is:

$i . H_{2} O$
$i i . H_{2} S$
$i i i . H_{2} S e$
$i v . H_{2} T e$

The correct option is B $(i) > (i i) > (i i i) > (i v)$
The basic character of hydrides of 16 group decreases down the group. Size increases down the group and LP $¯ ¯ ¯ e$ density decreases.

Basic: $H_{2} O > H_{2} S > H_{2} S e > H_{2} T e$