The decreasing fugacity order of the following compounds is:
i.⊖CNii.⊖OHiii.⊖OMeiv.⊖CH3v.H⊖
A
(v)>(iv)>(iii)>(ii)>(i)
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B
(i)>(ii)>(iii)>(iv)>(v)
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C
(iv)>(v)>(iii)>(ii)>(i)
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D
(i)>(iii)>(ii)>(v)>(iv)
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Solution
The correct option is D(i)>(iii)>(ii)>(v)>(iv) The leaving group should be able to stabilize the additional electron density that results from bond heterolysis. A good leaving group must be able to stabilize this negative charge.
Considering the stability of anions the order of fugacity is CN−>OMe−>OH−>H−>CH−3