Question

The decreasing nucleophilic order of the following compounds is:
$i.\stackrel{\ominus }{{CH}_3}$ $ii.\stackrel{\ominus }{N}{H}_2$ $iii.\stackrel{\ominus }{O}H$ $iv.F^{\ominus }$

• A. $\left(i\right)>\left(ii\right)>\left(iii\right)>\left(iv\right)$
• B. $\left(iv\right)>\left(iii\right)>\left(ii\right)>\left(i\right)$
• C. $\left(ii\right)>\left(i\right)>\left(iii\right)>\left(iv\right)$
• D. $\left(ii\right)>\left(i\right)>\left(iv\right)>\left(iii\right)$

Answer 1

The correct option is A $\left(i\right)>\left(ii\right)>\left(iii\right)>\left(iv\right)$

Since the nucleophilic centre is different but they belong to the same period, so the basic and nucleophilic characters are same. Basicity and nucleophilicity:
$\stackrel{\ominus }{C{H}_3}>\stackrel{\ominus }{N}{H}_2>\stackrel{\ominus }{O}H>F^{\ominus }$