The decreasing order of acid strength indicated by the following sequence of reaction is:

N H_{3} > P h_{3} C H > C_{2} H_{2} > H_{2} O

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H_{2} O > H C \equiv C H > P h_{3} C H > N H_{3}

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H C \equiv C H > H_{2} O > P h_{3} C H > N H_{3}

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P h_{3} C H > H C \equiv C H > H_{2} O > N H_{3}

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Solution

The correct option is B $H_{2} O > H C \equiv C H > P h_{3} C H > N H_{3}$
The correct order of increasing acidic strength is $N H_{3} < P h_{3} C H < C H \equiv C H < H_{2} O$ . That can be explained on the basis of electronegativity. In $P h_{3} C H$ , although conjugate base has resonance effect and highly stable, but due to steric hinderance less availability of $H^{+}$ ion.

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