The decreasing order of acidity of following phenol derivatives is:

P > Q > R > S

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S > R > Q > P

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S > R > P > Q

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Q > S > R > P

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Solution

The correct option is D $Q > S > R > P$
(2)>(4)>(1)>(3) is the order of acidity. Electron donating group decreases acidity. $- I$ effect increases acidity. $+ M$ decreases acidity.
In 1), $- O C H_{3}$ shows $- I$ and $+ M$
In 2) $- O C H_{3}$ shows $- I$ only
In 3) $- O C H_{3}$ shows $- I$ (less than that in (1) ) and $+ M$
In 4) no effect happens.

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Similar questions

Arrange in the order of decreasing $p K_{b}$

S_{N} 2

p, q, r

s

P : [(⇁ p \lor q) \land (r \to s) \land (p \lor r)] \to (⇁ s \to q)

Q : [(⇁ p \land q) \land [q \to (p \to r)]] \to⇁ r

R : [[(q \land r) \to p] \land (⇁ q \lor p)] \to r

S : [p \land (p \to r) \land (q \lor ⇁ r)] \to q

s = p + q + r

∣ ∣ ∣ ∣ \begin{matrix} s + r & p & q r & s + p & q r & p & s + q \end{matrix} ∣ ∣ ∣ ∣

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