The decreasing order of basic nature in the following is:
i. Pyrrole ii. Pyridine iii. Aniline

ii>iii>i

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

ii>i>iii

No worries! We‘ve got your back. Try BYJU‘S free classes today!

iii>ii>i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

iii>i>ii

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A ii>iii>i
Pyridine>Aniline>Pyrrole (diagram shown)
In (I), lone pair of N is not in delocalisation of $π ¯ e$ .
In (II) and (III), lone pair of N is used in deloalisation of $π ¯ e$ .
But in (III), $L P {¯ e}^{'} s$ on N are involved in aromaticity, so it is less basic than (II).

Suggest Corrections

Similar questions

The decreasing order of basic nature of $N a_{2} O$ (I); $M g O$ (II) and $A l_{2} O_{3}$ (III) is

E_{2}

I . T l_{2} O

I I . A l_{2} O_{3}

I I I . T l_{2} O_{3}

I V . G a_{2} O_{3}

Join BYJU'S Learning Program