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Question

The decreasing order of basic strength in the gas phaseC6H5NH2(I) , (C6H5)2NH(II), CH3NH2, NH3(IV)(III) is:

A
IV>III>II>I
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B
I>II>III>IV
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C
III>IV>I>II
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D
II>I>III>IV
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Solution

The correct option is C III>IV>I>II
As compared to amonia, methylamine is more basic (+I effect) but aniline is less basic and diphenylamine is still more weaker (+R effect of Nitrogen lone pair).
Hence, the correct order is III>IV>I>II

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