The decreasing order of basic strength in the gas phaseC6H5NH2(I),(C6H5)2NH(II),CH3NH2,NH3(IV)(III) is:
A
IV>III>II>I
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B
I>II>III>IV
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C
III>IV>I>II
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D
II>I>III>IV
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Solution
The correct option is CIII>IV>I>II As compared to amonia, methylamine is more basic (+Ieffect) but aniline is less basic and diphenylamine is still more weaker (+ReffectofNitrogenlonepair).
Hence, the correct order is III>IV>I>II