Question

The decreasing order of boiling points is

• A. n-Pentane > iso-Pentane > neo-Pentane
• B. Iso-Pentane > n-Pentane > neo-Pentane
• C. Neo-Pentane > iso-Pentane > n-Pentane
• D. n-Pentane > neo-Pentane > iso-Pentane

Answer 1

The correct option is A n-Pentane > iso-Pentane > neo-Pentane

The more the surface area, the higher the Van Der wall's interactions. The higher the interactions, the higher the boiling/melting points will be,
We know that a linear alkane has higher surface area than its branched successors in order.
Hence the order will be:
n-Pentane > iso-Pentane > neo-Pentane