The decreasing order of bond dissociation energy among halogens is:
A
F−F>Cl -Cl>Br - Br >I−I
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B
Cl -Cl>Br - Br >F−F>I−I
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C
Cl -Cl>Br - Br >I−I>F−F
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D
I−I>F−F>Cl -Cl>Br - Br
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Solution
The correct option is BCl -Cl>Br - Br >F−F>I−I Bond dissociation energy decrease down the group But bonds dissociation energy of F2 is less than excepted due to large repulsion of e− in F2