The correct option is C a>c>b
In Keto-enol tautomerism, delocalisation takes place between a >C=O group and an alpha H where the equilibrium lies between a keto form and an enol form.
Bond strength of C−D is greater than C−H.
Therefore,C−D will not break easily.
Thus, compound (b) does not form enol readily. Hence, it will have least enol content.
Since, compound (a) does not have a C−D bond it will undergo enolisation effectively and have greater enol content compared to others.
Hence, the decreasing order of enol percent is
a>c>b