The decreasing order of priority for the following functional groups is
I. -COOH
II. $- S O_{3} H$
III. -COOR
IV. -COCl

(IV) > (III) > (II) > (I)

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(I) > (II) > (III) > (IV)

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(II) > (I) > (III) > (IV)

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(IV) > (III) > (I) > (II)

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Solution

The correct option is B (I) > (II) > (III) > (IV)
If you look at the table which talks about the order of priority of functional groups, we can easily see that

-COOH > $- S O_{3} H$ > -COOR > -COCl

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Similar questions

- C \equiv N

- C O N H_{2}

- N H_{2}

Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

The order of -I power (-ve inductive effect ) of the following functional groups will be:

(i) $- S O_{3} H$

(ii) $- C l$

(iii) $- N H_{2}$

(iv) $- H$

I . Z n O

I I . K_{2} O

I I I . P_{2} O_{5}

I V . M g O

[C o (e n)_{2} (o x)]^{4 +}

[F e (T r i e n) (o x)]^{4 +}

[C o (E D T A)]

[P t (o x)_{2} (H_{2} O)_{2}]

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