The decreasing order of the acidic character of the following is:

(I) > (I I) > (I I I) > (I V)

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(I) > (I I I) > (I I) > (I V)

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(I V) > (I I I) > (I I) > (I)

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(I V) > (I I) > (I I I) > (I)

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Solution

The correct option is B $(I) > (I I I) > (I I) > (I V)$
The decreasing order of the acidic character of the following is (I) > (III) > (II) > (IV)
Cycloalkanes are more acidic than the corresponding alkanes.
Cyclopropane is most acidic and n butane is least acidic.
In general alkanes are inert towards acids and bases due to non polar nature of C-C and C-H bonds and their inability to donate or accept electrons.

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C H_{3} S H

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H_{2} O

i . B C l_{3}

i i . A l C l_{3}

i i i . G a C l_{3}

i v . I n C l_{3}

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⊖ O H

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Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

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