The decreasing order of the ease of ionization under acidic conditions of above alcohols will be:

I > I I I > I I

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I > I I > I I I

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I I > I I I > I

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I I > I > I I I

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Solution

The correct option is C $I I > I I I > I$
The correct option is C. $I I$ after ionization becomes aromatic compound. So it will easily loses its proton where as in I after ionisation, it becomes anti-aromatic, which is unstable. So the order is $I I > I I I > I .$

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Similar questions

Q. Arrange the following alcohols in decreasing order of the ease of ionization under acidic conditions.

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The decreasing order of the ease of ionization under acidic conditions of above alcohols will be:

The correct option is C II>III>IThe correct option is C. II after ionization becomes aromatic compound. So it will easily loses its proton where as in I after ionisation, it becomes anti-aromatic, which is unstable. So the order is II>III>I.

The correct option is C $I I > I I I > I$
The correct option is C. $I I$ after ionization becomes aromatic compound. So it will easily loses its proton where as in I after ionisation, it becomes anti-aromatic, which is unstable. So the order is $I I > I I I > I .$