The decreasing order of the rate of bromination of the following compounds is- I- Ph- N Me 3 II- PhCH3- N Me 3 III- PhMe IV- PhNMe2

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Chemical Properties of Boron Family

The decreasin...

Question

The decreasing order of the rate of bromination of the following compounds is:
$I . P h \oplus N {M e}_{3}$
$I I . P h {C H}_{3} \oplus N {M e}_{3}$
$I I I . P h M e$
$I V . P h N {M e}_{2}$

(I) > (I I) > (I I I) > (I V)

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(I V) > (I I I) > (I I) > (I)

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(I I I) > (I V) > (I) > (I I)

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(I I I) > (I V) > (I I) > (I)

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Solution

The correct option is B $(I V) > (I I I) > (I I) > (I)$
Stronger the activating substituent (i.e EDG) faster is the rate of (bromination) reaction.

Order of $¯ ¯ ¯ e$ donating substituent
$- \cdot \cdot N {M e}_{2} > - M e > - {C H}_{3} \oplus N {M e}_{3} > - \oplus N {M e}_{3}$

Hence, the rate of bromination is as given in (B)

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The decreasing order of the rate of bromination of the following compounds is:I.Ph⊕NMe3 II.PhCH3⊕NMe3 III.PhMe IV.PhNMe2

The correct option is B (IV)>(III)>(II)>(I)Stronger the activating substituent (i.e EDG) faster is the rate of (bromination) reaction.Order of ¯¯¯e donating substituent−⋅⋅NMe2>−Me>−CH3⊕NMe3>−⊕NMe3Hence, the rate of bromination is as given in (B)

The decreasing order of the rate of bromination of the following compounds is:
$I . P h \oplus N {M e}_{3}$
$I I . P h {C H}_{3} \oplus N {M e}_{3}$
$I I I . P h M e$
$I V . P h N {M e}_{2}$