The decreasing order of the second ionization potential of $M g, C a$ and $B a$ is:

M g > C a > B a

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C a > B a > M g

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B a > M g > C a

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M g > B a > C a

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Solution

The correct option is B $M g > C a > B a$
The ionization potential decreases down the group as the distance between valence electron and nucleus increases. The ionization potential increases after the successive removal of one or more electrons from isolated gaseous atom. Small size cations will have high ionization potential than large size cations.
The decreasing order of second ionization potential is: $M g > C a > B a$

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