The decreasing order of the size of $H^{-}$ , $O^{-}$ , $F^{-}$ , $C l^{-}$ is:

H^{-} < O^{-} < F^{-} < C l^{-}

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H^{-} > F^{-} > O^{-} > C l^{-}

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H^{-} > O^{-} > C l^{-} > F^{-}

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C l^{-} > F^{-} > O^{-} > H^{-}

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Solution

The correct option is C $H^{-} > O^{-} > C l^{-} > F^{-}$
Size of $H^{-}$ is very much larger than ${C l}^{-}$ or $o^{-}$ due to very less $Z_{e f f}$ in $H^{-},$ it's outer electron are free to maximize the radii $.$

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Similar questions

Q. The correct order of decreasing

X - O - X

bond angle is:

Q. The correct order of increasing

X - O - X

bond angle is

(X = H, F or C l)

Which of the following is not correct?

$O r d e r o f b a s i c i t y O r d e r o f n u c l e o p h i l i c i t y (a) F^{-} > C l^{-} > B r^{-} B r_{-} > C l^{-} > F^{-} (b) H - O - O^{-} > O H^{-} H - O - O^{-} > O H^{-} (c) C H_{3} > N H_{2}^{-} > O H - C H_{3} > N H_{2}^{-} > O H^{-} (d) H_{2} O > H_{2} S H_{2} O < H_{2} S$

Q. The electronegativity of

F, O, N, C l

and

H

are

4.0, 3.5, 3.0, 3.2

and

2.1

respectively. The strongest bond between the following will be:

Arrange F, Cl, O, and N in the decreasing order of electronegativity.

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The decreasing order of the size of H−, O−, F−, Cl− is:

The correct option is C H−>O−>Cl−>F−Size of H− is very much larger than Cl− or o− due to very less Zeff in H−, it's outer electron are free to maximize the radii.

The decreasing order of the size of $H^{-}$ , $O^{-}$ , $F^{-}$ , $C l^{-}$ is:

The correct option is C $H^{-} > O^{-} > C l^{-} > F^{-}$
Size of $H^{-}$ is very much larger than ${C l}^{-}$ or $o^{-}$ due to very less $Z_{e f f}$ in $H^{-},$ it's outer electron are free to maximize the radii $.$