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Atomic Radius

The decreasin...

Question

The decreasing stability order for the following anions is :

I > I I > I I I > I V

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I V > I I I > I I > I

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I I I > I V > I I > I

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I V > I I > I I I > I

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Solution

The correct option is B $I V > I I I > I I > I$

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Similar questions

The correct order for decreasing stability of the following free radicals is

- I

- C N

- N O_{2}

- N H_{2}

- F

- S O_{3} H

- C \equiv N

- C O N H_{2}

- N H_{2}

Arrange the following carbocations in decreasing order of stability

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