The definite integral $\int_{1}^{3} \frac{1}{x} d x$ is evaluated usingTrapezoidal rule with a step size of 1. The correct answer is
1.1667

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Solution

The correct option is A 1.1667
$f (x) = \frac{1}{x}$ , h=1

x 1 2 3

f(x) 1 0.5 0.333

$I = \frac{h}{2} [f_{0} + 2 f_{1} + f_{2})$
$= \frac{1}{2} [1 + 2 \times 0.5 + 0.33]$
I = 1.1667

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