The degree and order of the differential equation [1+(dydx)3]7/3=7(d2ydx2) respectively are:
A
3 and 7
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B
3 and 2
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C
7 and 3
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D
2 and 3
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Solution
The correct option is D3 and 2
First we have to raise both equations with power of 3 to make all the powers, integer, we get
[1+(dydx)3]7=7(d2ydx2)3
The degree of a differential equation is represented by the power of the highest order derivative in the given differential equation. So here the degree is 3.
Order of a differential equation is the order of the highest order derivative present in the equation. So here the order is 2.