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Question

The degree of d2ydx2+[1+(dydx)2]32=0 is

A
1
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B
2
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C
0
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D
4
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Solution

The correct option is B 2
Given diffrential equation can be written as
(1+(dydx)2)32=d2ydx2
squaring on both sides
(1+(dydx)2)3=(d2ydx2)2

Degree is nothing but the power of highest order derivative
Degree=2

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