The degree of d2ydx2- 1- dydx 3-2-0 is-

The correct option is A 2 d^2ydx^2= ( 1+dydx )^3/2 ⇒( d^2ydx^2)^2= ( 1+dydx )^3 ⇒ #160;Order=2degree = 2 ...

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Degree of a Differential Equations

The degree of...

Question

The degree of $\frac{d^{2} y}{d x^{2}} + {(1 + (\frac{d y}{d x}))}^{3 / 2} = 0$ is:

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{[\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2}]}^{1 / 2} = \frac{d^{3} y}{d x^{3}}

\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{3} + 3 y = x^{2}

y = 1 + {(\frac{d y}{d x})}^{1} + \frac{1}{2!} {(\frac{d y}{d x})}^{2} + \frac{1}{3!} {(\frac{d y}{d x})}^{3} + . . . . .

\frac{d^{2} y}{d x^{2}} = x l o g (\frac{d y}{d x})

The degree of the differential equation ${(1 + \frac{d y}{d x})}^{\frac{3}{2}} = \frac{d^{2} y}{d x^{2}}$ is

{[\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{3}]}^{\frac{6}{5}} = 6 y

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