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Question

The degree of dissociation is 0.4 at 400 K and 1.0 atm for the gaseous reaction PCl5PCl3+Cl2. Assuming ideal behaviour of all gases, calculate the density of equilibrium mixture at 400 K and 1.0 atmosphere. (Relative atomic mass of P=31.0 and Cl=35.5)

A
4.60 g/litre
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B
4.53 g/litre
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C
4.75 litre
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D
4.35 litre
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Solution

The correct option is B 4.53 g/litre
PCl5PCl3+Cl2
Initialmoles 100
Moles at equilibrium 10.40.40.4
Total moles =1.4 {Exp.molwtofPCl5=208.51.4}
PV=W/m×RT
PM=dRT
d=1×208.51.4×0.082×400
=4.53g/lit

1087039_1190214_ans_ace418ccea5c4877843ad885c8d9b2f0.png

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