wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The degree of dissociation of PCl5 at a certain temperature and pressure= 1 atm is 0.20. Calculate the value of equilibrium constant Kp.

A
0.084 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.84 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.42 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.042 atm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.042 atm
Let the degree of dissociation be α.
P be the total pressure at equilibrium.
PCl5PCl3+Cl2
Initial moles 1 0 0
At equi. 1α α α
Total number of moles at equilibrium = 1α+α+α = 1+α
Now, we know Kp = PPCl3×PCl2PCl5
PPCl5 = 1α1+αP
PPCl3 = α1+αP
PCl2 = α1+αP
So, Kp = α1+αP×α1+αP1α1+αP
Kp = α21α2P
Given, P = 1 atm, α = 0.2
Kp = 0.042 atm




flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon