Question

The degree of hydrolysis of $0.1RN{H}_{3}Cl$ solution is $1.0\text{\%}$. If the concentration of $RN{H}_{3}Cl$ is made $0.4M$, what is the new degree of hydrolysis (in percentage)?

• A. $0.01$
• B. $0.001$
• C. $0.2$
• D. $0.5$

Answer 1

The correct option is D $0.5$

As we know,

$K_a=C{\alpha }^2;\alpha =\sqrt{K_a/C}$

${\alpha }_2/{\alpha }_1=\sqrt{C_1/C_2}=\sqrt{0.1/0.4}=1/2$

${\alpha }_2=0.5\times 1\%=0.5\%$