The degree of ionisation of an acid HA is $0.00001$ at $0.1$ M concentration. Its dissociation constant will be ?

10^{- 9}

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10^{- 11}

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10^{- 8}

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10^{- 7}

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Solution

The correct option is C $10^{- 11}$
The degree of ionization of an acid HA = 0.00001 at 0.1M
Dissociation constant $K_{a} = C α^{2} = 0.1 \times (10^{- 5})^{2} = 10^{- 11} a t 0.1 M$

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