The degree of the differential equation [1+(dydx)2]5/3=d2ydx2
A
1
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B
5
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C
103
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D
3
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Solution
The correct option is D3 The given differential equation is [1+(dydx)2]5/3=d2ydx2 ⇒(d2ydx2)3=[1+(dydx)2]5 From above it is clear that the degree of the given differential equation is 3.