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Question

The degree of the differential equation
[1+(dydx)2]5/3=d2ydx2

A
1
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B
5
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C
103
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D
3
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Solution

The correct option is D 3
The given differential equation is
[1+(dydx)2]5/3=d2ydx2
(d2ydx2)3=[1+(dydx)2]5
From above it is clear that the degree of the given differential equation is 3.

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