Question

The degree of the differential equation ${[1+{\left(\frac{dy}{dx}\right)}^2]}^2=\frac{d^{2}y}{d{x}^2}$ is:

• A. 4
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (B)

1

The degree of a differential equation is the power of highest order derivative in the equation
${[1+{\left(\frac{dy}{dx}\right)}^2]}^2=\frac{d^{2}y}{d{x}^2}$
$1+{\left(\frac{dy}{dx}\right)}^4+2{\left(\frac{dy}{dx}\right)}^2={\left[\frac{d^{2}y}{d{x}^2}\right]}^1$
Highest order derivative in above equation$=\frac{d^{2}y}{d{x}^2}$
$\therefore Degree=1$