The degree of the differential equation y3/22−y1/21−4=0 is:
A
6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A6 y322=y121+4 Squaring both sides, we have y32=y1+16+8y121 ⇒(y32−y1−16)2=64y1⇒y62−32y32−2y32y1+y21−32y1+256=0 Hence the degree of the given equation is 6