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Question

The degree of the differential equation
y3/22−y1/21−4=0 is:

A
6
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B
3
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C
2
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D
4
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Solution

The correct option is A 6
y322=y121+4
Squaring both sides, we have
y32=y1+16+8y121
(y32y116)2=64y1y6232y322y32y1+y2132y1+256=0
Hence the degree of the given equation is 6

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