The degree of the polynomial $4 x^{2} - 7 x^{3} + 6 x + 1$ is.

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Solution

The correct option is C 3
A polynomial is a function of the form $f (x) = a_{n} x^{n} + a_{n - 1} x^{n - 1} + . . . + a_{2} x^{2} + a_{1} x + a_{0}$
where $a_{n}, a_{n - 1}, . . . a_{2}, a_{1}, a_{0}$ . are contants and $n$ is a natural number.

Let $p (x) = 4 x^{2} - 7 x^{3} + 6 x + 1$
$\Rightarrow$ The degree of a polynomial is the highest power of $x$ in its expression.

$\Rightarrow$ Highest power of $x$ in $p (x)$ is $=3

Thus, the degree $= 3$

$p (x) = 4 x^{2} - 7 x^{3} + 6 x + 1$ is a cubic polynomial.
Hence, option $C$ is correct.

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The degree of the polynomial obtained when $8 - 6 x + x^{2} - 7 x^{3} + x^{5}$ is subtracted from $x^{4} - 6 x^{3} + x^{2} - 3 x + 1$ is

7 x^{3} + 2 x^{2} + x

{4 x}^{2} - 6 x + 1

p (x) = 4 x^{2} - 6 x + 1

The degree of the polynomial obtained when $8 - 6 x + x^{2} - 7 x^{3} + x^{5}$ is subtracted from $x^{4} - 6 x^{3} + x^{2} - 3 x + 1$ is:

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