CameraIcon

SearchIcon

MyQuestionIcon

100

You visited us 100 times! Enjoying our articles? Unlock Full Access!

Remainder Theorem

The degree of...

Question

The degree of the polynomial $f (x) = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 4 & 20 1 & - 2 & 5 1 & 2 x & 5 x^{2} \end{matrix} ∣ ∣ ∣ ∣$ is

A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2$
By using sarrus rule:
$\begin{matrix} 1 & 4 & 20 & 1 & 4 1 & - 2 & 5 & 1 & - 2 1 & 2 x & 5 x^{2} & 1 & 2 x \end{matrix}$
$= - 10 x^{2} + 20 + 40 x - 20 x^{2} - 10 x + 40 \Rightarrow f (x) = - 30 x^{2} + 30 x + 60$
$∴$ Degree of $f (x)$ is $2$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The degree of the polynomial expression

f (x) = x^{4} + 5 \sqrt{2} x - \sqrt{2}

Divide the polynomial $f (x) = 14 x^{3} - 5 x^{2} + 9 x - 1$ by the polynomial $g (x) = 2 x - 1$ . Also find the quotient and remainder.

Q. The expression

(\sqrt{2 x^{2} + 1} + \sqrt{2 x^{2} - 1})^{6}

(\sqrt{2 x^{2} + 1} - \sqrt{2 x^{2} - 1})^{6}

is a polynomial of degree

f (x)

be an even function & even degree polynomial such that

f (\begin{matrix} \frac{1}{2} \end{matrix}) = \frac{1}{2}, f (1) = 1, f (2) = - 3, f (3) = 5

then minimum number of points of intersection for

f (x)

Q. The degree of the polynomial

5 x^{2} + x^{4} + 5

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Remainder Theorem

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon