You visited us 1 times! Enjoying our articles? Unlock Full Access!

Polynomial Functions

The degree of...

Question

The degree of the polynomial function $f (x) = (1 - x^{2}) (x - 1)$ is

Open in App

Solution

$f (x) = (1 - x^{2}) (x - 1)$
$\Rightarrow f (x) = - x^{3} + x^{2} + x - 1$
Since, here the highest power of $x$ is $3$ ,
$∴$ Degree of the polynomial function is $3.$

Suggest Corrections

Similar questions

f (x)

f (\begin{matrix} \frac{1}{2} \end{matrix}) = \frac{1}{2}, f (1) = 1, f (2) = - 3, f (3) = 5

f (x)

f (x)

f (- 3) = 6, f (0) = 6

f (2) = 11

f (x)

x = 1

x = 1

f (x) = x^{2} (x + 1)^{3} (x - 2)^{2} (x - 1)

g (x)

f (x)

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} g (x), & x \leq 0 {[\frac{1 + x}{2 + x}]}^{1 / x}, & x > 0 \end{matrix}

f (x)

f^{'} (1) = f (- 1) .

f (- 2)

x \in [a, b]

\int_{a}^{x} f (t) d t = \int_{x}^{b} f (t) d t

f (x)

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program