2
You visited us
2
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Polynomial Functions
The degree of...
Question
The degree of the polynomial function
f
(
x
)
=
(
1
−
x
2
)
(
x
−
1
)
is
Open in App
Solution
f
(
x
)
=
(
1
−
x
2
)
(
x
−
1
)
⇒
f
(
x
)
=
−
x
3
+
x
2
+
x
−
1
Since, here the highest power of
x
is
3
,
∴
Degree of the polynomial function is
3.
Suggest Corrections
0
Similar questions
Q.
Let
f
(
x
)
be an even function & even degree polynomial such that
f
(
1
2
)
=
1
2
,
f
(
1
)
=
1
,
f
(
2
)
=
−
3
,
f
(
3
)
=
5
then minimum number of points of intersection for
f
(
x
)
is
Q.
If
f
(
x
)
is a polynomial function of the second degree such that
f
(
−
3
)
=
6
,
f
(
0
)
=
6
and
f
(
2
)
=
11
, then the graph of the function
f
(
x
)
cuts the ordinate
x
=
1
at the point:
Q.
The multiplicity of the root
x
=
1
for the function
f
(
x
)
=
x
2
(
x
+
1
)
3
(
x
−
2
)
2
(
x
−
1
)
is
Q.
Let
g
(
x
)
be a polynomial of degree one and
f
(
x
)
be defined by
f
(
x
)
=
⎧
⎪ ⎪
⎨
⎪ ⎪
⎩
g
(
x
)
,
x
≤
0
[
1
+
x
2
+
x
]
1
/
x
,
x
>
0
Let
f
(
x
)
be a continuous function satisfying
f
′
(
1
)
=
f
(
−
1
)
.
Then
f
(
−
2
)
is equal to
Q.
Assertion :Let f be a polynomial function of degree n.
STATEMENT-1: There exists a number
x
∈
[
a
,
b
]
such that
∫
x
a
f
(
t
)
d
t
=
∫
b
x
f
(
t
)
d
t
. Reason: STATEMENT-2:
f
(
x
)
is a continuous function.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Explore more
Polynomial Functions
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app